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Ironmaiden
Posted: Fri Jul 04, 2008 5:00 am    Post subject: Simple differentiability help Reply with quote

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For Differentiability, the condition is:

lim h->0 (f(x-h)-f(x))/(-h) = lim h->0 (f(x+h)-f(x))/(h)


Since in both the cases, h -> 0, so isn't it that f(x-h) - f(x) and also f(x+h) - f(x) will always be = 0? If no, please explain including an example.


Thanks
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thyristor
Posted: Sat Jul 05, 2008 3:03 am    Post subject: Reply with quote

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What you do is that you investigate what happens when h approaches 0 not when it is zero. For example: lim h->0 (f(x+h)-f(x))/h , where f(x)=x2 , equals lim h->0 (x2+2xh+h2-x2)/h
equals lim h->0 h+2x=2x
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Ironmaiden
Posted: Sat Jul 05, 2008 3:39 am    Post subject: Reply with quote

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thanks 4 the reply. Very Happy
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